From help-request at octave dot org Sat Dec 31 17:48:14 2005
Subject: A thing about exponentials.
From: Jordi Gutierrez Hermoso <jordigh at gmail dot com>
To: help at octave dot org
Date: Sat, 31 Dec 2005 16:46:14 -0700

Apologies if this is a FAQ, but I couldn't find it in the FAQ, and I
tried a few searches in the mailing list archive to no avail.

In Octave 0^(1+i) is 0 and 0^i is NaN. They're both NaN in Matlab.

I can understand the NaN... probably from a call to log(0) somewhere.
But why isn't 0^(1+i) also NaN in Octave? What is Octave doing to
avoid that call to log(0)?

Thanks!
- JGH



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