From help-request at octave dot org Mon Jan 24 08:23:44 2005
Subject: Re: if statement within function
From: <billkreamer at bellsouth dot net>
To: "Ahn Kyung" <kjyaya at hotmail dot com>, <help@octave.org>
Date: Mon, 24 Jan 2005 09:21:51 -0500


----- Original Message -----
From: "Ahn Kyung" <kjyaya at hotmail dot com>
To: <help at octave dot org>
Sent: Monday, January 24, 2005 00:57
Subject: if statement within function


> I'm having trouble implementing if statement in a function. Here's an
> example:
> ---------------------
> function y=f(x)
>   if (x>1)
>     y=1;
>   else
>     y=x.^2;
>   endif
> endfunction
>
> x=[1;2];

Looks like a typo. Should this be   x=[1:2];   ?
>
> octave:3> f(x)
> ans =
>
>   1
>   4
>
> octave:4> f(1)
> ans = 1
> octave:5> f(2)
> ans = 1
> --------------------
> You see? f(2)=1, as expected, but if I use a vector x=[1;2];, I get
> f(x)=[1;4]; When using a vector, the if statement is useless...
>
> I don't want to pass each element, but want to use f(x) as a chunk, with a
> given vector x. What should I do to cure this problem??
>
> Thank you in advance.
>
>
>
>
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Octave is freely available under the terms of the GNU GPL.

Octave's home on the web:  http://www.octave.org
How to fund new projects:  http://www.octave.org/funding.html
Subscription information:  http://www.octave.org/archive.html
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