From help-request at octave dot org Mon Jan 24 00:56:33 2005
Subject: Re: if statement within function
From: "Ploett Norbert" <norbert dot ploett at siemens dot com>
To: "Ahn Kyung" <kjyaya at hotmail dot com>
Cc: <help at octave dot org>
Date: Mon, 24 Jan 2005 07:54:36 +0100

Ahn,=20

> f(x)=3D[1;4]; When using a vector, the if statement is useless...

I think you are right. You need an individual decision of which branch =
of the function to use for each element of x.

> I don't want to pass each element, but want to use f(x) as a chunk, =
with a=20
> given vector x. What should I do to cure this problem??

Try this:

function y=3Df(x)
 flags1 =3D (x>1);
 flags2 =3D (x<=3D1);
=20
 y =3D ones(rows(x), columns(x)) .* flags1 + x.^2 .* flags2 ;
endfunction

So you build complementary matrices of flags for your cases of x(i,j)>1 =
and x(i,j)<=3D1 and then overlay the results.


Greets


Norbert

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Octave is freely available under the terms of the GNU GPL.

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