From help-request at octave dot org Sun Jan 23 23:53:47 2005
Subject: if statement within function
From: "Ahn Kyung" <kjyaya at hotmail dot com>
To: help at octave dot org
Date: Mon, 24 Jan 2005 05:57:17 +0000

I'm having trouble implementing if statement in a function. Here's an 
example:
---------------------
function y=f(x)
  if (x>1)
    y=1;
  else
    y=x.^2;
  endif
endfunction

x=[1;2];


octave:3> f(x)
ans =

  1
  4

octave:4> f(1)
ans = 1
octave:5> f(2)
ans = 1
--------------------
You see? f(2)=1, as expected, but if I use a vector x=[1;2];, I get 
f(x)=[1;4]; When using a vector, the if statement is useless...

I don't want to pass each element, but want to use f(x) as a chunk, with a 
given vector x. What should I do to cure this problem??

Thank you in advance.




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