From help-request at octave dot org  Tue Nov  9 10:12:58 2004
Subject: Re: average of a function
From: Paul Kienzle <pkienzle at users dot sourceforge dot net>
To: "Fred J." <phddas at yahoo dot com>
Cc: help at octave dot org
Date: Tue, 9 Nov 2004 04:16:17 -0500


On Nov 8, 2004, at 10:36 PM, Fred J. wrote:

> I need to determine the average value of this function
> which I expect
> it to be -1.620993 but I am getting a different ans
> and not sure if I am
> using octave correctly.
>
> octave> function y=x(t), y = t^2 - 5*t + 6*cos(pi*t);
> end;
> octave> quad('x', -1, 5/2)
> ans = -5.6735

octave:5> format long
octave:6> quad('x', -1, 5/2)/(5/2 - -1)
ans = -1.62099257606588

- Paul



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