From help-octave-request at bevo dot che dot wisc dot edu Sun Feb  1 11:18:43 2004
Subject: Small problem in a if condition
From: "John W. Eaton" <jwe at bevo dot che dot wisc dot edu>
To: Pol <blenderman at wanadoo dot be>
Cc: help-octave at bevo dot che dot wisc dot edu
Date: Sun, 1 Feb 2004 11:12:27 -0600

On  1-Feb-2004, Pol <blenderman at wanadoo dot be> wrote:

| I'm trying to convert that script from matlab to octave and I'm hurting
| my head on that script:
| 
| function zp = kzp(v,z,i)
| 
| if (v == '?')
|     d = z*i   ;
| endif
| 
| if (z == '?')
|     d = v/i   ;
| endif
| 
| if (i == '?')
|     d = v/z   ;
| endif
| 
| M = norm(d) ;
| P = angle(d)*180/pi ;
| zp=[M;P];
| 
| endfunction
| 
| And now the errors:
| 
| octave:1> kzp(1,'?',3)
| error: invalid conversion from string to real matrix
| error: type conversion failed for binary operator `=='
| error: evaluating binary operator `==' near line 7, column 7
| error: if: error evaluating conditional expression
| error: evaluating if command near line 7, column 1
| error: called from `kzp' in file `/home/pol/.octave/m/kzp.m'

What version of Octave are you using?  I think the == operator should
work for character strings with either 2.0.17 or 2.1.50.

jwe



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