From help-octave-request at bevo dot che dot wisc dot edu Fri Jan 30 07:16:52 2004 Subject: Re: Problem in a if condition From: David Bateman To: Pol Cc: help-octave at bevo dot che dot wisc dot edu Date: Fri, 30 Jan 2004 14:10:13 +0100 This is a trick question right? > y11=y(1,1); > y12=y(1,2); y12 = 6 > y21=y(2,1); y21 = 3 > y22=y(2,2); > > if ( (y12-y21) > 0.00000001 ) 6 - 3 = 3 > 0.00000001 !!!! D. -- David Bateman David dot Bateman at motorola dot com Motorola CRM +33 1 69 35 48 04 (Ph) Parc Les Algorithmes, Commune de St Aubin +33 1 69 35 77 01 (Fax) 91193 Gif-Sur-Yvette FRANCE The information contained in this communication has been classified as: [x] General Business Information [ ] Motorola Internal Use Only [ ] Motorola Confidential Proprietary ------------------------------------------------------------- Octave is freely available under the terms of the GNU GPL. Octave's home on the web: http://www.octave.org How to fund new projects: http://www.octave.org/funding.html Subscription information: http://www.octave.org/archive.html -------------------------------------------------------------