From help-octave-request at bevo dot che dot wisc dot edu Thu Jan 23 13:32:02 2003
Subject: Re: A Simple Matrix Construction Question
From: "Iago Mosqueira" <i dot mosqueira at imperial dot ac dot uk>
To: "Craig Stoudt" <stoudtc at yahoo dot com>,    "Heber Farnsworth" <farnsworth@olin.wustl.edu>
Cc: <help-octave at bevo dot che dot wisc dot edu>
Date: Thu, 23 Jan 2003 19:31:27 -0000

Probably X = Y(ones(M,1),:) in this case, Y was a row vector.


iago

----- Original Message ----- 
From: "Heber Farnsworth" <farnsworth at olin dot wustl dot edu>
To: "Craig Stoudt" <stoudtc at yahoo dot com>
Cc: <help-octave at bevo dot che dot wisc dot edu>
Sent: 23 January 2003 19:27
Subject: Re: A Simple Matrix Construction Question


> I think the preferred way is
> 
> X = Y(:,ones(M,1));
> 
> Heber
> 
> On Thursday, January 23, 2003, at 12:35 PM, Craig Stoudt wrote:
> 
> > There is probably a really simple way to do the
> > following, but I'm suffering from a mental block.
> >
> > I have a row array 'Y' of arbitrary length, 1xn.
> >
> > I want to create an mxn matrix where all of the rows
> > are the same as 'Y'.
> >
> > Of course, I want to do this without resorting to
> > loops.
> >
> > Thanks in advance.
> >
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Octave is freely available under the terms of the GNU GPL.

Octave's home on the web:  http://www.octave.org
How to fund new projects:  http://www.octave.org/funding.html
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