From help-octave-request at bevo dot che dot wisc dot edu Fri Dec 27 17:10:27 2002
Subject: Re: Newbie question solving lin sys
From: "John B. Thoo" <jb2 at ms dot yuba dot cc dot ca dot us>
To: <zlash at mail dot notwires dot com>
Cc: <help-octave at bevo dot che dot wisc dot edu>
Date: Fri, 27 Dec 2002 15:10:15 -0800

Bill (or others)---

I'm sorry, but I have at least one more question about this.  I get this 
for the list of coefficients when I enter in Octave

octave:92> for i = [1:12]
 > x(i)
 > end
ans = 22
ans = 129.32
ans = -330.01
ans = 356.74
ans = -211.74
ans = 77.512
ans = -18.446
ans = 2.9092
ans = -0.30191
ans = 0.019818
ans =  -7.4570e-04
ans =  1.2250e-05

But these numbers lead to erroneous calculations.  My question is, does 
Octave keep track of more digits (greater precision) somehow when I use 
x(1), x(2),... instead?

Thanks again.

---John.


On Friday, December 27, 2002, at 02:15 PM, William Lash wrote:

> Whenever you type in the numbers for you calculation in s you are
> losing precision.  Instead of typing in:
>
>> octave:55> 22 + 129.32*s - 330.01*s**2 + 356.74*s**3 - 211.74*s**4 +
>> 77.512*s**5 - 18.446*s**6 + 2.9092*s**7 - 0.30191*s**8 + 
>> 0.019818*s**9 -
>> 0.0007457*s**10 + 0.00001225*s**11
>
> Try the following:
>
> x(1)+x(2)*s+x(3)*s**2+x(4)*s**3+x(5)*s**4+x(6)*s**5+x(7)*s**6+x(8)*s**7+x(
> 9)*s**8+x(10)*s**9+x(11)*s**10+x(12)*s**11



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